Arithmetic of Computers

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Lesson 4

Practice Makes Perfect

Prowess with powers

Page 146

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Your answer :

1(2¹) + 1(2⁰) + 1(2^− 1) = 3(1)/(2) 7(10³) + 6(10²) + 4(10¹) + 2(10⁰) = 7, 642 2(7²) + 3(7¹) + 4(7⁰) = 123 1(8^− 1) + 2(8^− 2) = (10)/(64) ⎫⎪⎪⎬⎪⎪⎭ This set contains a mistake.

Well, let’s see:

1(2¹) + 1(2⁰) + 1(2^− 1) = 1(2) + 1(1) + 1⎛⎝(1)/(2)⎞⎠ = 2 + 1 + (1)/(2) = 3(1)/(2); 7(10³) + 6(10²) + 4(10¹) + 2(10⁰) = 7(1000) + 6(100) + 4(10) + 2(1) = 7000 + 600 + 40 + 2 = 7, 642; 2(7²) + 3(7¹) + 4(7⁰) = 2(49) + 3(7) + 4(1) = 98 + 21 + 4 = 123; 1(8^− 1) + 2(8^− 2) = 1⎛⎝(1)/(8)⎞⎠ + 2⎛⎝(1)/(8²)⎞⎠ = 1⎛⎝(1)/(8)⎞⎠ + 2⎛⎝(1)/(64)⎞⎠ = 1⎛⎝(8)/(64)⎞⎠ + 2⎛⎝(1)/(64)⎞⎠ = (8)/(64) + (2)/(64) = (10)/(64).

No mistakes here. Return to page 129 and try again.