Arithmetic of Computers

Arithmetic of Computers

from Tenscope Limited

Lesson 4

Practice Makes Perfect

Prowess with powers

Page 150

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Your answer :
1(23) + 0(22) + 0(21) + 1(20)  = 9 3(1001) + 4(1000)  = 304 7(103) + 6(102) + 2(101) + 1(100)  = 7, 621 1(14) + 1(13) + 1(12) + 1(11) + 1(10)  = 5  This set contains a mistake.
Well, let’s see:
1(23) + 0(22) + 0(21) + 1(20)  = 1(8) + 0(4) + 0(2) + 1(1)  = 8 + 0 + 0 + 1  = 9; 3(1001) + 4(1000)  = 3(100) + 4(1)  = 300 + 4 = 304; 7(103) + 6(102) + 2(101) + 1(100)  = 7(1000) + 6(100) + 2(10) + 1(1)  = 7000 + 600 + 20 + 1  = 7, 621; 1(14) + 1(13) + 1(12) + 1(11) + 1(10)  = 1(1) + 1(1) + 1(1) + 1(1) + 1(1)  = 5.
All correct. Return to Page 129 and try again.
 

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