Lesson 4
Practice Makes Perfect
Prowess with powers
Page 150
Your answer :
1( 23 ) + 0( 22 ) + 0( 21 ) + 1( 20 )
= 9
3( 1001 ) + 4( 1000 )
= 304
7( 103 ) + 6( 102 ) + 2( 101 ) + 1( 100 )
= 7, 621
1( 14 ) + 1( 13 ) + 1( 12 ) + 1( 11 ) + 1( 10 )
= 5
⎫ ⎪ ⎪ ⎬ ⎪ ⎪ ⎭ This set contains a mistake .
Well, let’s see:
1( 23 ) + 0( 22 ) + 0( 21 ) + 1( 20 )
= 1( 8) + 0( 4) + 0( 2) + 1( 1)
= 8 + 0 + 0 + 1
= 9;
3( 1001 ) + 4( 1000 )
= 3( 100) + 4( 1)
= 300 + 4 = 304;
7( 103 ) + 6( 102 ) + 2( 101 ) + 1( 100 )
= 7( 1000) + 6( 100) + 2( 10) + 1( 1)
= 7000 + 600 + 20 + 1
= 7, 621;
1( 14 ) + 1( 13 ) + 1( 12 ) + 1( 11 ) + 1( 10 )
= 1( 1) + 1( 1) + 1( 1) + 1( 1) + 1( 1)
= 5.
All correct. Return to Page 129 and try again.
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