Arithmetic of Computers

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Lesson 4

Practice Makes Perfect

Prowess with powers

Page 153

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Your answer :

3(10^− 1) + 7(10^− 2) + 6(10^− 3) = .376 1(5²) + 1(5¹) + 4(5⁰) = 34 1(2²) + 0(2¹) + 1(2⁰) = 5 3(4²) + 2(4¹) + 1(4⁰) = 60 ⎫⎪⎪⎬⎪⎪⎭ This set contains a mistake.

You are correct.

3(4²) + 2(4¹) + 1(4⁰) = 57, not 60.

Did you notice that in the last few questions a new idea has been developed? It is possible to write any number you please as a sum of multiples of powers of numbers. This has important consequences.

However, before you get to that you should answer the Self-Test Questions for Lesson 4, They are in the Appendix.