Lesson 6
The Octal System
From eight to ten
Page 188
Your answer :
548
= 4410
2258
= 14910
7108
= 45610
1, 0008
= 51210
⎫⎪⎪⎬⎪⎪⎭ This group contains a mistake.
Well, let’s check by writing the octal numbers in expanded form:
548
= 5(81) + 4(80)
= 5(8) + 4(1) = 4410;
2258
= 2(82) + 2(81) + 5(80)
= 2(64) + 2(8) + 5(1) = 14910;
7108
= 7(82) + 1(81) + 0(80)
= 7(64) + 1(8) + 0(1) = 45610;
1, 0008
= 1(83) + 0(82) + 0(81) + 0(80)
= 1(512) + 0(64) + 0(8) + 0(1) = 51210.
They’re all correct. Return to Page 182 and try again.
