Lesson 6
The Octal System
From eight to ten
Page 188
Your answer :
548
= 4410
2258
= 14910
7108
= 45610
1, 0008
= 51210
⎫ ⎪ ⎪ ⎬ ⎪ ⎪ ⎭ This group contains a mistake.
Well, let’s check by writing the octal numbers in expanded form:
548
= 5( 81 ) + 4( 80 )
= 5( 8) + 4( 1) = 4410 ;
2258
= 2( 82 ) + 2( 81 ) + 5( 80 )
= 2( 64) + 2( 8) + 5( 1) = 14910 ;
7108
= 7( 82 ) + 1( 81 ) + 0( 80 )
= 7( 64) + 1( 8) + 0( 1) = 45610 ;
1, 0008
= 1( 83 ) + 0( 82 ) + 0( 81 ) + 0( 80 )
= 1( 512) + 0( 64) + 0( 8) + 0( 1) = 51210 .
They’re all correct. Return to Page 182 and try again.
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