Arithmetic of Computers

Arithmetic of Computers

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Lesson 6

The Octal System

From eight to ten

Page 204

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Your answer :
13.48 = 1(81) + 3(80) + 4(8 − 1).
You are correct. The numerals written to the right of the point (.) in an octal number are coefficients of negative powers of 8. Thus, 13.48 would be expanded as
13.48 = 1(81) + 3(80) + 4(8 − 1).
We should recall that
8 − 1 = (1)/(81) = (1)/(8).
So we can find the decimal equivalent of our octal 13.48 as follows:
13.48  = 1(8) + 3(1) + 4(1)/(8)  = 8 + 3 + (4)/(8).
So how shall we write this sum in decimal notation?
Answer :
13.48 = 11.510.

Go to Page 209

13.48 = 11.410.

Go to Page 217


 

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