You are correct. Beastly thing won’t stop, will it? Just as we have recurring decimals, such as (1)/(3) = .3333⋯, (1)/(7) = .142857142⋯, we have recurring octal fractions. The curious thing is that all multiples of .110 (except .510 = (1)/(2) = .48) expressed in the octal system contain the repeating digits 6314.
Many octal fractions do not terminate in zeros, so we must face up to the problem of rounding octal fractions. How would you round 21.448 to the nearest (octal) number?
