Arithmetic of Computers

Arithmetic of Computers

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Lesson 7

Decimals to Octals

. . . and back again

Page 223

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Your answer :
24410 = 4638.
The process was:
First, divide the number by 8, and obtain the first remainder.
30 , r = 4 = 1st remainder 8)244
Next, divide the first quotient (30) by 8, and obtain the second remainder.
3 , r = 6 = 2nd remainder 8)30 , r = 4 = 1st remainder 8)244
Next, divide the second quotient (3) by 8, and obtain the third remainder.
0 , r = 3 = 3rd remainder 8)3 , r = 6 = 2nd remainder 8)30 , r = 4 = 1st remainder 8)244
Now, write the remainders in the reverse order in which they were obtained - that is, from top to bottom - and you have the number 24410 expressed in octal notation. You have the digits in the wrong order in your answer.
Return to Page 235 and choose the correct answer.
 

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